18d^2+77d-18=1

Solution for 18d^2+77d-18=1 equation:

18d^2+77d-18=1

We move all terms to the left:

18d^2+77d-18-(1)=0

We add all the numbers together, and all the variables

18d^2+77d-19=0

a = 18; b = 77; c = -19;
Δ = b2-4ac
Δ = 772-4·18·(-19)
Δ = 7297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-\sqrt{7297}}{2*18}=\frac{-77-\sqrt{7297}}{36}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+\sqrt{7297}}{2*18}=\frac{-77+\sqrt{7297}}{36}
$